Full text: Musschenbroek, Petrus: Physicae experimentales, et geometricae de magnete, tuborum capillarium vitreorumque speculorum attractione, magnitudine terrae, cohaerentia corporum firmorum dissertationes

INTRODUCTIO AD COHÆRENTIAM pendiculari, habebit momentum gravitatis, ad momentum ſegmen-
ti a A F G H, cujus baſis F G H eſt parallela ad B D C E, uti Cohæ-
rentia B D C E, eſt ad Cohærentiam F G H.

Vocetur A D, a. D B, b. D C, c. a G, x. erit G F = {b x x. /a a} Eſt
vero planum a G F = {1/3} a G X G F = {1b x 3 /3a a} & ſoliditas corporis
A a H G F = {b c x 3 . /3 a a} Cohærentia baſeos F G H ={b b x 4 c. /a 4 } momen-
tum vero = {b c x 4 /12 a a}. quia centrum gravitatis in plano a D B, diſtat ab
F G = {1/4} a G. ſoliditas corporis a A D B C eſt {1/3} a b c. momentum
= {a ab c. /12} & Cohærentia baſeos D B C = b b c. Eſt vero
{a a b c. /12} b b c: : {b c x 4 . /12 a a} {b b c x 4 . /a 4 }

Quare hoc ſolidum ſe [?] iſſum in quocunque loco ſectione parallelâ
ad baſin B D C, ſemper habebit momenta ſuæ gravitatis in ratione
Cohærentiæ baſium.


Tab. XXVI fig. 9. Dato Cuneo paraboliformi D C O B F cujus
baſis D C O B parieti perpendiculari ad horizontem ſit infixa, axis
parabolæ A F, invenire momentum gravitatis, Cohærentiam ba-
ſeos, at que eadem in ſegmento K E G F, cujus baſis K E G ſit pa-
rallela ad C D B O.

Vocetur C O, a. O B, b. A F, d. invenietur ſoliditas Cunei pa-
rabolici D C O B F = {2/3} a b d. diſtantia Centri gravitatis a baſi D C O B
in ſegmento horizontali A F, eſt = {2/7} A F = {2/7} d. adeoque erit momen-
tum Cunei ex gravitate = {4/35} a b d d. eſt vero Cohærentia baſeos = a a b. adeoque erit momentum ex gravitate ad Cohærentiam uti {4/35} d d
ad a. Vocetur H F x. erit Cohærentia baſeos. K E G = {a a b x 2 . /d d}
& momentum ex gravitate = {4 a b x{7/2}. /35 d{3/2}}

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